
Question #b8408 - Socratic
The thing to keep in mind here is that nitric acid is a strong acid, which means that it will ionize completely in aqueous solution to produce hydronium cations, H3O+, and nitrate anions, NO− …
How many grams of \text {NH}_4\text {OH} do I need to make
"6.3072 g" >>"Molarity" = "Moles of solute"/"Volume of solution (in litres)" "0.45 M" = "n"/"0.4 L" "n = 0.45 M × 0.4 L = 0.18 mol" You need "0.18 mol" of "NH"_4"OH" Molar mass of "NH"_4"OH" …
Question #5f837 - Socratic
The balanced chemical equation for the partial dissociation of the base looks like this "BOH"_text ( (aq]) rightleftharpoons "B"_text ( (aq])^ (+) + "OH"_text ( (aq])^ (-) By definition, K_b will be …
Can you give the IUPAC name for the following (CH_3)_3C-OH
2016年8月29日 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by …
Question #71ce2 - Socratic
H^+ + OH^--> H_2O when the acid was added to the resulting solution. The H^+ and OH^- react in a 1:1 ratio. This tells us that the number of moles of H^+ used will be equal to the number of …
Question #71b91 - Socratic
Since water is in excess, "67.7 g MgO" are needed to produce "98.0 g Mg(OH)"_2. Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the …
Question #e7848 - Socratic
Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion. So, you can say that NH_4^+ is the acid, and OH^- is the base. Conjugates are basically the "other" term. For every acid, you …
Question #a721d - Socratic
pH = 1.61151 OH^- = 4.08797 * 10 ^-13M HF = 0.855538M H^+ = 0.024462M F^- = 0.024462M HF + H_2O = H_3O^+ + F^- We can find the concentration of H^+ or H_3O^+ by three ways …
Question #7213b - Socratic
Now, assuming that # [HA] = [OH^-]# due to hydrolysis for ease of calculation,
What is the product of the following reaction? 1)CH_3 OH - Socratic
2017年12月23日 · These are ostensibly acid-base reactions.... For ammonium we could write.... NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed ...