SOLVED: Find the values of x for which the series converges. (Enter your answer using interval notation.) ∞ (-7)^(n*x) n = 1
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SOLVED: Find the values of x for which the series converges. (Enter your answer using interval notation.) ∞ (-7)^(n*x) n = 1
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Let fn (x) = ( sinnx )/n^2. Show that the series ∑fn(x) converges for all values of x but the series of derivatives ∑f'n (x) diverges when x = 2n π, n an integer. For what values of x does the series ∑f”n (x) converge? | Numerade
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